Dweets awesomed by u/metamero

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

Try the new frontend: beta.dwitter.net
Current theme challenge: #Food

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KilledByAPixel

function u(t) {

c.width=1e3
z=500
for(i=501;i--;x.lineTo(z+k*50*S(t/2)+S(p=(i/2|0)*Math.PI*4/z-t*k/9)*250,281+C(p)*250))k=(i%2?-5:5)
x.fill('evenodd')

May 31 2019 11:10 PM UTC

}// 134/140

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Stuck Circles

u/Xen

woot, love it
u/katkip

#moire

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metamero

remix of d/14343 by u/Xen

function u(t) {

for(c.width^=frame,i=9;i--;)x.fillRect(400+i*99+S(t)*300,400,50,200)

May 31 2019 7:50 PM UTC

}// 68/140

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#default entanglement

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metamero

remix of d/14345 by u/metamero

function u(t) {

with(localStorage)c.width|=1,x.fillRect(parseInt(a)+1920,b,z,z)

May 31 2019 7:31 PM UTC

}// 63/140

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"left" side of the bouncing thing area : works with d/14345

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metamero

remix of d/14341 by u/metamero

function u(t) {

w=c.width=1920
t?x.fillRect(a+=p,b+=q,z,z):a=b=p=q=z=42
a>=w-z||a<=-w?p=-p:0
b>=1038||b<=0?q=-q:0
for(o of"abpqzw")localStorage[o]=this[o]

May 31 2019 7:30 PM UTC

}// 139/140

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"right" side of the bouncing thing

u/metamero

open also "left" side d/14346
u/KilledByAPixel

That's cool.

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Xen

function u(t) {

x.fillText(t*99|0,940+C(frame*t)*frame/9,540+S(frame*t)*frame/9)

May 31 2019 6:57 PM UTC

}// 64/140

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test while i wait for taxi lol

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metamero

function u(t) {

w=c.width=1920
t?x.fillRect(a+=p,b+=q,z,z):a=b=p=q=z=42
a>=w-z||a<=0?p=-p:0
b>=1038||b<=0?q=-q:0

May 31 2019 6:52 PM UTC

}// 97/140

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97B bouncing thing (i bet you can do it smaller)

u/jylikangas

w=c.width|=0 t?x.fillRect(a+=p,b+=q,z,z):a=b=p=q=z=42 a%w<z?p=-p:0 b%1e3<z?q=-q:0 82b
u/joeytwiddle

77B by KilledByAPixel: c.width|=f=w=>(m=(3e3*t%w+w)%w,m>w/2?w-m:m);x.fillRect(f(3814),f(2118),42,42)
u/Xen

71B c.width|=f=w=>(m=3e3*t%w,m>w/2?w-m:m);x.fillRect(f(3814),f(2118),42,42)
u/jylikangas

f=w=>(m=3e3*t%w)>w/2?w-m:m;x.fillRect(f(3814),f(c.width=2e3),42,42) 67B

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rodrigo.siqueira

function u(t) {

v=(a,b,Φ,r)=>{for(i=0;i++<r;)x.fillRect(a-=S(Φ),b-=C(Φ),s=r/18,s)
r>9?v(a,b,Φ+.5,r*=.72)&v(a,b,Φ-.5,r):0}
if(t<2)v(S(t**7)*3e3,1e3,0,72*t*t)

May 31 2019 3:04 PM UTC

}// 140/140

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Autumn forest #tree #recursive #fractal #organic

u/13thptr

nice
u/katkip

Awesome!!
u/SMON

Φ <3
u/aleamb

amazing!

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pavel

remix of d/11101 by u/pavel

function u(t) {

t?c.width=540:a=b=0
q=42+t&-1
with(x)rect(X=q*q%533,Y=X*q%300,8,8),moveTo(a+=C(d=Math.atan2(Y-b,X-a)),b+=S(d)),fill(arc(a,b,15,d+t%1,d-t%1))

May 31 2019 4:27 AM UTC

}// 140/140

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#pacman is too slow

u/KilledByAPixel

Pᗣᗧ•MᗣN ᗧ • • •
u/joeytwiddle

wow
u/rep_movsd

Forever hungry

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rodrigo.siqueira

function u(t) {

D=(a,b)=>{L=a.length,i=r=0,R='';while(i<53){d=i<L?~~(a[i]):0,R+=(i==L?".":"")+~~((K=d+(r*10))/b),r=K%b,i++}throw(a+"/"+b+"="+R)};D("1",9998)

May 30 2019 5:23 PM UTC

}// 140/140

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BigFloat in 140 chars! This is the Long Division Algorithm used here to calculate 1/9998. Note that this simple division results in Powers of Two: 0001, 0002, 0004, 0008, 0016, 0032, 0064.... Try to change 9998 for 9997 and you will see Powers of Three (1, 3, 9, 27, 81...). Guess what 9996 does? D is the division function. (a,b) are (numerator, denominator). 53 is precision (number of digits). Add more "9" to fit larger power numbers. E.g. To see powers up to 2**40 (that is 1099511627776), change denominator from 9998 to 9999999999998 and total number of digits from 53 to 534.

u/rodrigo.siqueira

I have discovered a truly remarkable demonstration of this result, but this comment is too small to contain.
u/joeytwiddle

#math #division
u/marc8

quoting Fermat... LOL

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13thptr

function u(t) {

s=~~t+"";throw s.split``.map((e,i)=>(r="IXC",d="VLD"[i=s.length-1-i],b=r[i],e<4?b.repeat(e):e-4?e-9?e>4&e<9?d+b.repeat(e-5):0:b+r[i+1]:b+d))

May 30 2019 10:47 AM UTC

}// 140/140

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Counts up to 899

u/13thptr

Thanks to u/KilledByAPixel for the golfing help :)
u/joeytwiddle

optimvm laborvs!
u/13thptr

turns out someone made a more elegant and "general" implementation. The function is 136c long but it's not callable without compression inside Dwitter: https://codegolf.stackexchange.com/a/77961

dwitter.net | metamero (18715)