Dweets awesomed by u/danschormans

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

Try the new frontend: beta.dwitter.net
Current theme challenge: #ScaryMovies

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BackendForth

function u(t) {

c.width|=0
f=(m,n,r)=>{x.fillRect(m+960,n+540,r,r)
if(r>0){f(4*m,4*S(t)*n,r-1)
f(C(r)*m-S(r)*n,S(r)*n+C(r)*m,r-1)}}
f(0,1,13)

Feb 3 2022 6:26 PM UTC

}// 125/140

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joeytwiddle

remix of d/17467 by u/Xen

function u(t) {

for(v=t*2.67,c.width=190,n=i=1+v%16|0;i--;x.fillText(s?'🐍':n>12?i<12|i&1?'':'🍄':'🦡',75+C(i+s*t)*70,90-i*4+C(v*6)*9))s=v%96>76,x.font=`2em'`

Jan 30 2022 1:16 AM UTC

}// 139/140

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The #badger song

u/joeytwiddle

https://www.youtube.com/watch?v=pzagBTcYsYQ To sync with the video, restart the dweet at the end of the snake verse
u/taupelink

blast from the past!
u/tomxor

OMG NO! I only just got it out of my head after 2 decades
u/sigveseb

lol

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iznax

function u(t) {

c.width=800;p=(a)=>x[b](400+S(a)*"4335"[k>>1]*32,90+C(a)*8+k*48)||p;for(z=43;--z;p(t,b='moveTo')(t+=7,b='lineTo')(t,++k)(t-7),x.fill())k=z%7

Jan 22 2020 6:11 AM UTC

}// 140/140

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#Castle Rook

u/KilledByAPixel

♜👍

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denzen

function u(t) {

a=3,c=200,r=(S(t)+1)/2
for(i=0;i<a;i++)
for(j=0;j<a;j++){
x.fillRect(990+C(t+i)*i*c,540+S(t+j)*j*c,20*r,20*r)}

Jan 19 2020 2:41 AM UTC

}// 110/140

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My first dweet!

u/katkip

Looks good!

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hotdogninja76

function u(t) {

c.width+=0
r=Math.random
X=t?X+(d=r()<.05)*200*(r()-.5):(v=0,500)
d?v=5:v--
x.font="9em a"
x.fillText("😠"+["🗡🗡","  ⚔  "][+(v>0)]+"😠",X,500)

Jan 11 2020 12:19 PM UTC

}// 140/140

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Worlds Worst Fencing Simulator

u/DataMeta

Neat idea!
u/katkip

Indeed

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katkip

function u(t) {

for(c.width|=j=5,z=600;j--;)for(i=2*z;i--;)x.fillRect(960+C(i*52e-4)*600+S(i*j+t)*99,540+S(i*52e-4)*300+C(i*j+t)*99,s=C(i*52e-4-1.5)*2+5,s)

Jan 10 2020 1:02 PM UTC

}// 139/140

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#ellipse inside a #torus

u/DataMeta

#opticalillusion

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WasifBoomz

function u(t) {

x.setLineDash([10*t,10*t])
x.strokeStyle=R(20*t,255-t*20,255-t*40)
x.strokeRect(25*t,25*t,100*t,100*t)

Jan 9 2020 3:44 PM UTC

}// 102/140

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Xen

remix of d/17106 by u/robbyg

function u(t) {

for(c.width|=i=z=262,x.globalCompositeOperation='xor';i--;x.fillRect(i%66*30,220*(i/66|0)+C(i*6+t*9)*i,27,z))x.fillStyle=R(i,z*T(i/t/9),z-i)

Jan 8 2020 4:09 PM UTC

}// 140/140

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pavel

function u(t) {

for(c.width=640,i=8;i--;x.stroke())x.beginPath(r=150*2/3*(i>1)),x.arc(320+r*C(a=Math.PI/3*i+t),180+r*S(a),150*(i?1/3:1),0,7)

Jan 4 2020 9:07 PM UTC

}// 124/140

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d/17063 #explanation

u/pavel

If you take every point on this picture, turn it into z=x+i*y and feed it through (sqrt(3)+z)/(1+sqrt(3)*z) then decode the resulting complex number as (x', y') and put a point there, you will get d/17063.
u/pavel

Of course you can't take infinitely many points so you will get a pixelated version. To get a proper version you need to solve the equation for the new, mapped, circle given the old circle so that you can use x.arc..

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Jezza

remix of d/17065 by u/Jezza

function u(t) {

c.width|=0
for(i=0;i<t*9;i+=Math.PI/t**.7) {
 x.beginPath();
 x.ellipse(960+C(i)*i*4,540+S(i)*i*4,i**0.5,i**0.5,0,0,2*Math.PI)
 x.fill();
}

Jan 4 2020 2:33 AM UTC

}// 140/140

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