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u(t) is called 60 times per second. t: Elapsed time in seconds. S: Shorthand for Math.sin. C: Shorthand for Math.cos. T: Shorthand for Math.tan. R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5) c: A 1920x1080 canvas. x: A 2D context for that canvas.
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  • it's amazing to see an AI creating a working dweet. Epoch 30/50

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  • Expression Miner (bruteforce)
  • u/joeytwiddle
    Unfortunately I couldn't use alert(S) so I had to drop some numbers!
  • u/joeytwiddle
    Tryn=4 and either D=[1,3,7] or D=[1,1,4,27] #unimproved
  • u/joeytwiddle
    Rather than searching, it might be more productive to display/draw some of the unusual small expressions, so we can look for ways to use them in future

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  • City Limits 🌆

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  • Show more comments…
  • u/tomxor
    I should clarify: to by pruning I mean not mearly skipping evaluation of individual permutations but to be able to skip entire subtrees of permutations by detecting equivalence at the root of that subtree.
  • u/joeytwiddle
    Pruning does sound sensible, but I'm not sure how to approach it.
  • u/joeytwiddle
    I am also having difficultly with >3 non-trivial outputs. I think the search space is too large. But at least I found some simplifications, such as: [1,3,5,7] => X-~X
  • u/tomxor
    Finally got it to solve a non linear one: D=[2,3,6,11,18,27] (2+X*X), just need a bit more patience

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remix of d/18738 by u/katkip

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  • AI generated dweet. Epoch 20/50
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  • u/katkip
    AI generated dweet. Epoch 25/50
  • u/katkip
    for(i=0;i<3e3;i+=2e3))for(=0;j)*S(T)*C(-t)),i=3e3,i,x.fillRect(X*60,Y**C(a),540+r**(=0))x.fillStyle=R((i=c.width|=0,:,){x.lineTo(i*.1);x.stroke();
  • u/katkip
    AI generated dweet. Epoch 26/60
  • u/katkip
    /&,x.fillRect(0,0,i=*C(C((*(ijin*f*6),a/2+(k(ai)+=i=>(i%*3,wbw,+15)),=(3,+w&q,x.fillRect(n%*+1,5,*+w0,w=*3,a?5:0,.5)

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  • Beep

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remix of d/18727 by u/katkip

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remix of d/17945 by u/yonatan

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  • idk

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