Dweets awesomed by u/joeytwiddle

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

Try the new frontend: beta.dwitter.net
Current theme challenge: #Food

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LimeLaser

function u(t) {

r=Math.random
with(x){
fillStyle=R(255*r(),255*r())
fillRect(1e3*r(),0,8,8)
save()
translate(960,540)
rotate(t)
drawImage(c,0,0)
restore()}

Jun 2 2019 7:28 AM UTC

}// 139/140

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Cool Spinning Glitch

u/LimeLaser

I'm not really sure why it does this, but I got this effect while trying to rotate and draw the canvas onto itself.
u/katkip

its because drawimage

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DataMeta

remix of d/9262 by u/DataMeta

function u(t) {

if(t<3.14)for(i=7;i--;x.stroke())x.arc(960,768,Math.abs(144*i*S(t-i)),i,i)

Jun 1 2019 11:26 PM UTC

}// 74/140

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u/katkip

Wow

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katkip

remix of d/14351 by u/KilledByAPixel

function u(t) {

eval(unescape(escape`𨰮𭱩𩁴𪀽𜑥𜰻𮠽𝐰𜀻𩡯𬠨𪐽𝐰𜐻𪐭𛐻𮀮𫁩𫡥𥁯𚁺𚰲𞐪𪰪𠰨𭀯𜠩𚱓𚁰🐨𪐯𜡼𜀩𚡍𨑴𪀮𤁉𚠴𛰨𠰨𮠪𜰮𜐴𞐩𛰲𚐭𭀪𪰯𞐩𚠲𝐰𛀲𞀱𚱃𚁰𚱓𚁰𚠲𚐯𜠩𚠲𝐰𚐩𪰽𚁩𙐲🰭𝀺𝀩𞰻𮀮𬱴𬡯𪱥𚀩`.replace(/uD./g,'')))

Jun 1 2019 6:52 PM UTC

}// 118/140

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KilledByAPixel

remix of d/14341 by u/metamero

function u(t) {

c.width|=f=w=>(m=(500*t%w+w)%w)>w/2?w-m:m
x.fillRect(0,0,2e3,2e3)
x.fillStyle="#0DF"
x.font="12em'"
x.fillText("📀",f(3440),f(1760)+170)

Jun 1 2019 12:50 AM UTC

}// 135/140

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DVD Bounce

u/KilledByAPixel

#dvdbounce

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KilledByAPixel

function u(t) {

c.width=1e3
z=500
for(i=501;i--;x.lineTo(z+k*50*S(t/2)+S(p=(i/2|0)*Math.PI*4/z-t*k/9)*250,281+C(p)*250))k=(i%2?-5:5)
x.fill('evenodd')

May 31 2019 11:10 PM UTC

}// 134/140

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Stuck Circles

u/Xen

woot, love it
u/katkip

#moire

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metamero

function u(t) {

w=c.width=1920
t?x.fillRect(a+=p,b+=q,z,z):a=b=p=q=z=42
a>=w-z||a<=0?p=-p:0
b>=1038||b<=0?q=-q:0

May 31 2019 6:52 PM UTC

}// 97/140

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97B bouncing thing (i bet you can do it smaller)

u/jylikangas

w=c.width|=0 t?x.fillRect(a+=p,b+=q,z,z):a=b=p=q=z=42 a%w<z?p=-p:0 b%1e3<z?q=-q:0 82b
u/joeytwiddle

77B by KilledByAPixel: c.width|=f=w=>(m=(3e3*t%w+w)%w,m>w/2?w-m:m);x.fillRect(f(3814),f(2118),42,42)
u/Xen

71B c.width|=f=w=>(m=3e3*t%w,m>w/2?w-m:m);x.fillRect(f(3814),f(2118),42,42)
u/jylikangas

f=w=>(m=3e3*t%w)>w/2?w-m:m;x.fillRect(f(3814),f(c.width=2e3),42,42) 67B

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rodrigo.siqueira

function u(t) {

v=(a,b,Φ,r)=>{for(i=0;i++<r;)x.fillRect(a-=S(Φ),b-=C(Φ),s=r/18,s)
r>9?v(a,b,Φ+.5,r*=.72)&v(a,b,Φ-.5,r):0}
if(t<2)v(S(t**7)*3e3,1e3,0,72*t*t)

May 31 2019 3:04 PM UTC

}// 140/140

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Autumn forest #tree #recursive #fractal #organic

u/13thptr

nice
u/katkip

Awesome!!
u/SMON

Φ <3
u/aleamb

amazing!

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vinca

remix of d/14328 by u/LimeLaser

function u(t) {

x[s="fillStyle"]="#AC31",x[r="fillRect"](0,0,2e3,2e3),x[s]=R(),x[r](951+700*C(a=3*C(t)),531+300*S(a),200,200),x.drawImage(c,16,9,1888,1062)

May 31 2019 1:06 PM UTC

}// 139/140

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pavel

remix of d/11101 by u/pavel

function u(t) {

t?c.width=540:a=b=0
q=42+t&-1
with(x)rect(X=q*q%533,Y=X*q%300,8,8),moveTo(a+=C(d=Math.atan2(Y-b,X-a)),b+=S(d)),fill(arc(a,b,15,d+t%1,d-t%1))

May 31 2019 4:27 AM UTC

}// 140/140

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#pacman is too slow

u/KilledByAPixel

Pᗣᗧ•MᗣN ᗧ • • •
u/joeytwiddle

wow
u/rep_movsd

Forever hungry
u/46uuuu

#chase

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rodrigo.siqueira

function u(t) {

D=(a,b)=>{L=a.length,i=r=0,R='';while(i<53){d=i<L?~~(a[i]):0,R+=(i==L?".":"")+~~((K=d+(r*10))/b),r=K%b,i++}throw(a+"/"+b+"="+R)};D("1",9998)

May 30 2019 5:23 PM UTC

}// 140/140

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BigFloat in 140 chars! This is the Long Division Algorithm used here to calculate 1/9998. Note that this simple division results in Powers of Two: 0001, 0002, 0004, 0008, 0016, 0032, 0064.... Try to change 9998 for 9997 and you will see Powers of Three (1, 3, 9, 27, 81...). Guess what 9996 does? D is the division function. (a,b) are (numerator, denominator). 53 is precision (number of digits). Add more "9" to fit larger power numbers. E.g. To see powers up to 2**40 (that is 1099511627776), change denominator from 9998 to 9999999999998 and total number of digits from 53 to 534.

u/rodrigo.siqueira

I have discovered a truly remarkable demonstration of this result, but this comment is too small to contain.
u/joeytwiddle

#math #division
u/marc8

quoting Fermat... LOL

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