Hot dweets by u/rodrigo.siqueira

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

Try the new frontend: beta.dwitter.net
Current theme challenge: #Food

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rodrigo.siqueira

function u(t) {

if(t<16){p=S(t)*999,q=p*t //random p,q
for(i=5e3;i--;){
po=p
p+=S(q+p),q+=po
q%=2*Math.PI,p%=2*Math.PI
x.fillRect(q*310,p*250,1,1)}}

Jun 7 2019 3:35 PM UTC

}// 132/140

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The chaotic sea in the phase space of the standard map on the two-torus. We observe a mixture of chains of chaotic regions, ergodic looks and stable islands. As seen on: https://www.math.uni-tuebingen.de/user/stke/… #chaos #attractor

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rodrigo.siqueira

function u(t) {

Y2=X2=X=0
Y=S(t)
for(i=3e3;i--;){
N=(P=X*X+Y*Y)*S(3/(P)**0.5)
X2+=-Y+X*N+S(i)
Y2+=X+Y*N
X=X2/4
Y=Y2/8
x.fillRect(960+X*1e3,540+Y*1e3,1,.3)
}

Jun 10 2019 8:09 PM UTC

}// 140/140

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I was trying to create this: https://imgur.com/gallery/jpAn7tX but something very wrong happened. The equations in the page seem simple, if anyone wants to try...

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rodrigo.siqueira

remix of d/14415 by u/rodrigo.siqueira

function u(t) {

v=(a,b,Φ,r)=>{for(i=~r;i++;x.fillStyle=R(0,99-r))x.fillRect(a-=S(Φ),b-=C(Φ),r/70,.6)
while(r>4)v(a,b,Φ+S(b)/2,r*=.7)}
t<4&&v(940,1e3,0,75*t)

Jun 7 2019 3:03 AM UTC

}// 140/140

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Growing plant #organic #fractal #tree

u/DataMeta

just wow

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rodrigo.siqueira

remix of d/14442 by u/rodrigo.siqueira

function u(t) {

v=(a,b,Φ,r)=>{for(i=~r;i++;x.fillStyle=R(r))x.fillRect(a-=S(Φ),b+=C(Φ),r/40,.3)
while(r>9){v(a,b,Φ+S(b)/5,r*=.8)}}
t<1.6&&v(945,540,t*4,112)

Jun 5 2019 5:57 PM UTC

}// 140/140

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Feather ornament #fractal

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rodrigo.siqueira

remix of d/14486 by u/rodrigo.siqueira

function u(t) {

if(t<18){Y=S(t)*999,X=t*Y
for(i=7e3;i--;)ℵ=Y,Y+=S(Y+X),X+=ℵ,x.fillStyle=R(Y*60,i/55,t*8),X%=τ=Math.PI*2,Y%=τ,x.fillRect(X*310,Y*330,1,1)}

Jun 7 2019 8:14 PM UTC

}// 137/140

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Phase-space of the Standard Map - color version. It is constructed by a Poincaré's surface of section of the kicked rotator, as described here: https://en.wikipedia.org/wiki/Standard_map

u/Xen

love it!

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rodrigo.siqueira

remix of d/4665 by u/ben

function u(t) {

v=(a,b,Φ,r)=>{for(i=~r;i++;x.fillStyle=R(0,Φ*30))x.fillRect(a+=S(Φ),b-=C(Φ),r/30,1)
while(r>3)v(a,b,Φ+S(b)/4+.4,r*=.72)}
v(t*2e4,1450,t,490)

Jun 5 2019 3:02 PM UTC

}// 140/140

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Windy garden #fractal #tree

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rodrigo.siqueira

remix of d/14489 by u/rodrigo.siqueira

function u(t) {

if(t<20){p=S(t)*99,q=p*9
for(i=5e3;i--;){P=p
p+=C(4*(q+p))/5,q+=P
q%=π=Math.PI,p%=π
x.fillStyle=R(i/25,t,p*20)
x.fillRect(q*695,p*400,1,1)}}

Jun 7 2019 9:57 PM UTC

}// 140/140

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Poincaré's dream

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rodrigo.siqueira

remix of d/14338 by u/rodrigo.siqueira

function u(t) {

v=(a,b,Φ,r)=>{for(i=0;i++<r;)x.fillRect(a-=S(Φ),b-=C(Φ),s=r/40,s)
r>2&&v(a,b,Φ+Math.random()-.5,r*=.82)}
t<4&&v(940,1e3,0,45*t)

Jun 3 2019 6:43 PM UTC

}// 127/140

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Growing root #organic #fractal #tree

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rodrigo.siqueira

function u(t) {

v=(a,b,Φ,r)=>{for(i=0;i++<r;)x.fillRect(a-=S(Φ),b-=C(Φ),s=r/18,s)
r>9?v(a,b,Φ+.5,r*=.72)&v(a,b,Φ-.5,r):0}
if(t<2)v(S(t**7)*3e3,1e3,0,72*t*t)

May 31 2019 3:04 PM UTC

}// 140/140

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Autumn forest #tree #recursive #fractal #organic

u/13thptr

nice
u/katkip

Awesome!!
u/SMON

Φ <3
u/aleamb

amazing!

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rodrigo.siqueira

function u(t) {

D=(a,b)=>{L=a.length,i=r=0,R='';while(i<53){d=i<L?~~(a[i]):0,R+=(i==L?".":"")+~~((K=d+(r*10))/b),r=K%b,i++}throw(a+"/"+b+"="+R)};D("1",9998)

May 30 2019 5:23 PM UTC

}// 140/140

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BigFloat in 140 chars! This is the Long Division Algorithm used here to calculate 1/9998. Note that this simple division results in Powers of Two: 0001, 0002, 0004, 0008, 0016, 0032, 0064.... Try to change 9998 for 9997 and you will see Powers of Three (1, 3, 9, 27, 81...). Guess what 9996 does? D is the division function. (a,b) are (numerator, denominator). 53 is precision (number of digits). Add more "9" to fit larger power numbers. E.g. To see powers up to 2**40 (that is 1099511627776), change denominator from 9998 to 9999999999998 and total number of digits from 53 to 534.

u/rodrigo.siqueira

I have discovered a truly remarkable demonstration of this result, but this comment is too small to contain.
u/joeytwiddle

#math #division
u/marc8

quoting Fermat... LOL

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