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function u(t) {
} //
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u(t) is called 60 times per second. t: Elapsed time in seconds. S: Shorthand for Math.sin. C: Shorthand for Math.cos. T: Shorthand for Math.tan. R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5) c: A 1920x1080 canvas. x: A 2D context for that canvas.
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remix of d/23084 by u/New_Core

function u(t) {

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  • u/miratcan
    HOW!!!!????
  • u/pavel
    S(i*i)>0||-1 is shorter as 1|S(i*i)-1
  • u/pavel
    I tried thinking of a way to make it never double-back but its hard to fit. Special sequence that looks random and has this property?
  • u/donbright
    !!!!

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remix of d/22643 by u/Xor

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  • Using setLineDash as otherwise its too slow to draw all the squares

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remix of d/21114 by u/magna

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  • 4x resolution from leveraging periodicity
  • u/magna
    Smart! And a lot more beautiful! :)

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function u(t) {

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  • Visualizing Array.sort

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remix of d/21012 by u/pavel

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  • Torus Study #2

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  • Torus Study #1

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  • Snowstorm

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remix of d/20901 by u/pavel

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  • u/pavel
    Discovered this randomly when golfing the original. Not sure why it happens.
  • u/danny@hille.dk
    cool effect: the "feature" is caused by not truncating k=--i/120 -> k=--i/120|0 disables this feature :-)
  • u/KilledByAPixel
    👍
  • u/danny@hille.dk
    better solution: for(i=c.width|=p=g=>(g(0)?k&3:~~k/4)*200+150*g((k&1||-1)*(i%120*41/13+5*t));k=--i/120;)x.fillRect(560+p(S),240+p(C),9,9)

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function u(t) {

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  • Ribbons
  • u/pavel
    Dynamically swapping the draw order to get proper overlapping. Change i>960 to 1 or 0 to see how this works.
  • u/Qwitter
    cool, and thanks!

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remix of d/20898 by u/cantelope

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  • Metatron's Cube
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  • u/pavel
    end-circle-offset == 0 is easy to check and means start and end are same circle, so draw that circle.
  • u/pavel
    Otherwise draw the current circle with radius 0 which is same as lineTo.
  • u/pavel
    T=!T&&!x.beginPath(x.stroke()) starts/strokes the path every two circles.
  • u/pavel
    Here is a version before all the bit hacking for(c.width=640,i=16;i--;)for(j=16;j--;x.beginPath(x.stroke()))for(k=2;k--;)q=(i+j*k)%16,r=((q+2)/6|0)*64,x.arc(320+r*C(a=Math.PI/3*q+t),180+r*S(a),!j*32,0,7)

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