Top dweets of all time

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

Try the new frontend: beta.dwitter.net
Current theme challenge: #Food

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taupelink

remix of d/15399 by u/taupelink

function u(t) {

for(i=q=300,d=e=f=0;i--;d+=((r=Math.random(l=.8)*11|0)-3-d+e*f*C(d)/2)*l,f+=(r%2-f-d*e/9)*l,e+=(r%7/3-e+d*e*f/2)*l)x.fillRect(d*q,2*e*q,1,1)

Apr 3 2020 2:06 AM UTC

}// 140/140

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I'm resuming my #chaosgame experiments, no promises it will come out good if you choose to #waitforit

u/KilledByAPixel

If you use http://capjs.3d2k.com/ you can change the time scale in advanced settings, might help you iterate faster. For this one you can set the time scale to 10000 and it appears instantly.
u/taupelink

u/KilledByAPixel Thank you--that is great!

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function u(t) {

c.width=1920
x.fillRect(0,0,1920,1080)
for(i=0;i<1980;i++)
x.fillStyle=R(S(t)*i,T(t)*i,C(t)*i)
x.font='5in"'
x.fillText("AO", S(t)*i, 700);

Apr 2 2020 10:56 PM UTC

}// 139/140

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katkip

function u(t) {

c.width*=1;x.font='6cm"';X=960+S(t)*300,Y=540+C(t)*300,x.fillText("🕺",X+S(t*3+3)*60,Y+C(t*3+3)*60),x.fillText("💃",X+S(t*3)*60,Y+C(t*3)*60)

Apr 2 2020 12:03 PM UTC

}// 138/140

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simple #dancing #emoji s

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Xen

function u(t) {

for(i=9;i--;x.stroke())x.beginPath(),
x.arc(1e3+C(i/2)*t**3,500+S(i*3)*t**3,1e3-t*t,0,9)

Apr 1 2020 4:11 PM UTC

}// 88/140

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R&om 1

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Xen

remix of d/18089 by u/Xen

function u(t) {

for(i=199;i--;x.beginPath())x.fillStyle=`hsl(${z=t*i/9},50%,50%)`,x.fill(x.arc(i+S(z)*i*9,C(z)*i*9+500,9+i,0,t)),x.stroke()

Mar 31 2020 6:20 PM UTC

}// 123/140

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Circles4

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galactustrombone

function u(t) {

l=960
h=540
v=[0,l,l/2]
w=[0,0,h]
r=~~(Math.random()*3)
p=(typeof p!='object')?[l,h]:[v[r]+p[0]/2,w[r]+p[1]/2]
x.fillRect(p[0],p[1],9,9)

Mar 26 2020 5:43 AM UTC

}// 136/140

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Sierpinski Gasket

u/galactustrombone

oops i realized it looks much nicer if you decrease the rect size from 9x9 to 5x5

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tomxor

remix of d/18062 by u/tomxor

function u(t) {

for(a=t?b:[1],b=S,S=[],x.drawImage(c,0,1),p=1920;p--;x.fillStyle=S[p]?R():'tan',x.fillRect(p,0,1,1))
A=a[p],B=b[p],S[p]=A^B^C,C=(A^B)&C|A&B

Mar 25 2020 1:57 PM UTC

}// 139/140

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1920bit #Fibonacci sequence using 1-bit serial adder

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tomxor

remix of d/18050 by u/tomxor

function u(t) {

x.fillRect(0,0,c.width=138,78);for(i=48;i--;x.fillText([...'🦙🐐🦒'][i>>4],(X&128?~X:X)&127,40+S(Y)*20))X=i*t*4,Y=i+t*4

Mar 23 2020 8:09 PM UTC

}// 116/140

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llamawave

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Odog8

function u(t) {

x.font='90px"'
x.fillText('🧻',(90*60*t)%1920,~~(t*2)*90)

Mar 23 2020 2:11 PM UTC

}// 56/140

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my TP stash !

u/pavel

To get (X,Y) out of n you do (n%width,n/width|0). Here n=60*t and you got 21 TPs across so x.font='90px"';x.fillText('🧻',60*t%21*90,(60*t/21|0)*90)
u/pavel

This reveals that if we pick n=63*t we can shorten Y=63*t/21|0=3*t|0
u/Odog8

Thanks!

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luizhp

function u(t) {

for(c.width|=i=1;i--;x.fillText("🌎  🇨🇳",50,T=900)|x.fillText("🦠",0.65*T+599*C(t*4+i),t/i<9?350*S((i-t*2)%3.14):T))x.font="16cm '"

Mar 21 2020 8:39 PM UTC

}// 129/140

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Chinese Virus