Top #short dweets

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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iverjo

remix of d/11024 by u/katkip

function u(t) {

throw' '.repeat(9+C(t)*9)+"|".repeat(9)

Nov 17 2018 6:33 PM UTC

}// 39/140

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Replaced the dot with the "FOUR-PER-EM SPACE" unicode character #short #default #unicode

u/katkip

Oh, thanks
u/jylikangas

Isn't it even shorter without the second repeat call. I mean just adding the vertical parts inside the string
u/katkip

I actually realised this after 1 second from posting

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Tesseract

remix of d/2667 by u/yonatan

function u(t) {

r=(t**5)%6&6,
x.fillRect(S=425*r+S>>1,C=425*(2&r)+C>>1,3,3)
//slow but short

May 22 2018 5:43 PM UTC

}// 76/140

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u/lionleaf

#short
u/S.T.L.K.R.

Damn I was trying to do that

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Bugsy

function u(t) {

for(c.width|=r=999;--r;x.lineTo(960+C(r+t)*a,540+S(r+t)*a))a=r/2
x.stroke()

Jun 16 2018 4:32 PM UTC

}// 75/140

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The graph r=theta spinning around the origin. 65 characters to play with, so there's lots of remixing potential. Try messing around with the trig functions, it leads to some fun results

u/iverjo

Go fullscreen, stare at the center for 30 seconds, then look away from your screen (e.g. look at your keyboard). #opticalillusion
u/iverjo

#short

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iverjo

remix of d/11028 by u/iverjo

function u(t) {

throw' '.repeat(9+C(t)*9)+"❚❚❚❚❚❚❚❚❚"

Nov 18 2018 12:44 PM UTC

}// 37/140

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Removed the second repeat call to make it shorter, as suggested by jylikangas. Used a bolder rectangle character, as suggested by joeytwiddle here: d/9591 #short #default #unicode

u/jylikangas

If you use 111111111 you get a 3D version with less bytes. :)
u/Qwitter

nice!

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robbyg

remix of d/8103 by u/robbyg

function u(t) {

x.fillText('╲╱'[new Date%2],t*600%2e3,t*10/3)

Jun 14 2018 9:42 PM UTC

}// 45/140

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#short #maze

u/robbyg

Only 7 characters longer than 10 PRINT CHR$(205.5+RND(1)); : GOTO 10 ;)
u/Xen

x.fillText('╲╱'[1+S(t*t)|0],t*600%2e3,t/.3)

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robbyg

function u(t) {

c.width|=0;for(i=214;i--;)x.fillRect(i*9,0,9,(S(i+t)+1)*540)

Jun 4 2018 6:41 PM UTC

}// 60/140

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#short

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