Drawing a circle in 33 bytes by Xor

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

Please log in (or register) to post a dweet (copy-paste the code somewhere safe to save it meanwhile)


    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

show FPS hide FPS share fullscreen

Xor

function u(t) {

x.fillRect(960,r=540,C(t)*r,S(t)*r)

Apr 29 2021 9:38 PM UTC

}// 35/140

Please log in (or register) to post as a new dweet (copy-paste code somewhere safe to save it meanwhile).

Drawing a circle in 33 bytes

u/KilledByAPixel

#circlechallenge
u/New_Core

👍 the real challenge would be to beat the size of normal way to do it ( <30 bytes, same size centerd).
u/Xor

What's the normal way?
u/New_Core

well, I was thinking of arc as normal way. x.fill(x.arc(960,540,540,1,7)) (using arc is not the challenge,)


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

dwitter.net