Uncompressed code is 156/140 so i got r… by smtsjhr

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

Please log in (or register) to post a dweet (copy-paste the code somewhere safe to save it meanwhile)


    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

show FPS hide FPS share 1 remix fullscreen

smtsjhr

remix of d/20295 by u/smtsjhr

function u(t) {

eval(unescape(escape`𨰮𭱩𩁴𪁼🐰𛁭🐰𯀨𝀫𜐰𜀪𤰨𭀯𝀩𚠪𜠩𛁳🐱𞐲𜀯𫐻𩡯𬠨𪰽𫐪𫐻𨐽𦱵👫𙑭𚡳𛁶🐨𪰯𫑼𜀩𚡳𛁳𛁳𧐬𫀽𭠭𥀨𭀩𚠨𭐭𞐶𜀩𛐵𝀰𚰲𚡳𛁫𛐭𞰩𬰼𫀦𙡬🀲𚡳🱸𛡦𪑬𫁒𩑣𭀨𛠮𛡡𚐺𮀮𬱴𬡯𪱥𤡥𨱴𚀮𛠮𨐩`.replace(/u../g,'')))

Oct 19 2020 6:47 AM UTC

}// 121/140

Please log in (or register) to post as a new dweet (copy-paste code somewhere safe to save it meanwhile).

Uncompressed code is 156/140 so i got rid of the background "pixel grid" shown here to get the original d/20295 under 140 ... still looking to golf some more...

u/smtsjhr

c.width|=0,m=0|(4+100*S(t/4)**2),s=1920/m;for(k=m*m;a=[u=k%m*s,v=(k/m|0)*s,s,s],l=v-T(t)*(u-960)-540+2*s,k--;)s<l&&l<2*s?x.fillRect(...a):x.strokeRect(...a)
u/smtsjhr

all i did to get under 140 was remove x.strokeRect(...a)
u/smtsjhr

in need of a better way to alternate between x.stroke and x.fill as the loop ranges over the rectangles of the grid


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

dwitter.net